Discussion:
Union & Concat: Question on Implementation
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Beau Osborne
2005-04-11 07:50:36 UTC
Permalink
In the first example in examples.txt, it appears that the 'new start state'
is appended as the final element.
---- i.e.. (0,1,2,3,4) where 4 is the new start state.

Can we implement nfdaUnion and nfdaConcat so that our new start state is the
first element?
---- i.e.. (0,1,2,3,4) where 0 is the new start state.

Just so you know, I have already created working algorithms using the '0'
start state implementation.

Thanks,

Osborne
Benjamin Ho
2005-04-11 08:32:10 UTC
Permalink
that's how ours is as well. it should be ok since they are equivalent.
i hope so.
Post by Beau Osborne
In the first example in examples.txt, it appears that the 'new start
state' is appended as the final element.
---- i.e.. (0,1,2,3,4) where 4 is the new start state.
Can we implement nfdaUnion and nfdaConcat so that our new start state is
the first element?
---- i.e.. (0,1,2,3,4) where 0 is the new start state.
Just so you know, I have already created working algorithms using the '0'
start state implementation.
Thanks,
Osborne
Nedialko B. Dimitrov
2005-04-11 18:08:11 UTC
Permalink
Yes, I will accept this.

Ned.
Post by Benjamin Ho
that's how ours is as well. it should be ok since they are equivalent.
i hope so.
Post by Beau Osborne
In the first example in examples.txt, it appears that the 'new start
state' is appended as the final element.
---- i.e.. (0,1,2,3,4) where 4 is the new start state.
Can we implement nfdaUnion and nfdaConcat so that our new start state is
the first element?
---- i.e.. (0,1,2,3,4) where 0 is the new start state.
Just so you know, I have already created working algorithms using the '0'
start state implementation.
Thanks,
Osborne
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