Discussion:
Mult
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John Wussow
2005-05-01 20:34:13 UTC
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I am confused as to how the naiveMult function is supposed to work. When I
work it out by hand using the summation given in section 2.1 I don't get the
right number of Cj elements. Can i get some clarification here?
David Zhao
2005-05-02 02:05:09 UTC
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Yes, you will need to add an extra zero to get the correct number of elements.

David
Post by John Wussow
I am confused as to how the naiveMult function is supposed to work. When I
work it out by hand using the summation given in section 2.1 I don't get the
right number of Cj elements. Can i get some clarification here?
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